linux_Ultra的个人空间 https://www.eechina.com/space-uid-2909.html [收藏] [复制] [RSS]

博客

device iterator

已有 3129 次阅读2010-4-18 17:44 |

还是得用Google的.com啊。
//--------------------drivers/base/Bus.c----------------------------------
....
.....
/**
 * bus_for_each_dev - device iterator.
 * @bus: bus type.
 * @start: device to start iterating from.
 * @data: data for the callback.
 * @fn: function to be called for each device.
 *
 * Iterate over @bus's list of devices, and call @fn for each,
 * passing it @data. If @start is not NULL, we use that device to
 * begin iterating from.
 *
 * We check the return of @fn each time. If it returns anything
 * other than 0, we break out and return that value.
 *
 * NOTE: The device that returns a non-zero value is not retained
 * in any way, nor is its refcount incremented. If the caller needs
 * to retain this data, it should do so, and increment the reference
 * count in the supplied callback.
 */
int bus_for_each_dev(struct bus_type *bus, struct device *start,
             void *data, int (*fn)(struct device *, void *))
{
    struct klist_iter i;
    struct device *dev;
    int error = 0;

    if (!bus)
        return -EINVAL;

    klist_iter_init_node(&bus->p->klist_devices, &i,
                 (start ? &start->p->knode_bus : NULL));
    while ((dev = next_device(&i)) && !error)
        error = fn(dev, data);
    klist_iter_exit(&i);
    return error;
}
-----------------------------------------------------------------------------------------------------
C/Iterators
The problem

Suppose we have an abstract data type that represents some sort of container, such as a list or dictionary. We'd like to be able to do something to every element of the container; say, count them up. How can we write operations on the abstract data type to allow this, without exposing the implementation?

To make the problem more concrete, let's suppose we have an abstract data type that represents the set of all non-negative numbers less than some fixed bound. The core of its interface might look like this:

nums.h

function isnumbered(obj) { return obj.childNodes.length && obj.firstChild.childNodes.length && obj.firstChild.firstChild.className == 'LineNumber'; } function nformat(num,chrs,add) { var nlen = Math.max(0,chrs-(''+num).length), res = ''; while (nlen>0) { res += ' '; nlen-- } return res+num+add; } function addnumber(did, nstart, nstep) { var c = document.getElementById(did), l = c.firstChild, n = 1; if (!isnumbered(c)) if (typeof nstart == 'undefined') nstart = 1; if (typeof nstep == 'undefined') nstep = 1; n = nstart; while (l != null) { if (l.tagName == 'SPAN') { var s = document.createElement('SPAN'); s.className = 'LineNumber' s.appendChild(document.createTextNode(nformat(n,4,' '))); n += nstep; if (l.childNodes.length)

路过

鸡蛋

鲜花

握手

雷人

发表评论 评论 (1 个评论)

facelist

您需要登录后才可以评论 登录 | 立即注册

关于我们  -  服务条款  -  使用指南  -  站点地图  -  友情链接  -  联系我们
电子工程网 © 版权所有   京ICP备16069177号 | 京公网安备11010502021702
返回顶部